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Kinematics, Fluid resistance, Instantanious speed and velocity - Coggle…

- - - - How long the projectile is in the air
    - - the height at which the projectile is momentarily at rest
    - - the horizontal distance travelled by the projectile
  - - - velocity
        
        constant
      - acceleration
        
        0
      - displacement
        
        Maximum range at the end of the motion when the total time has elapsed
        
        Half the range at the maximum height when half the time has elapsed
        
        Can be calculated with
        
        distance=speed x time
        
        where
        
        time=2usinθ/g
        
        a=0
        
        speed=ucosθ
    - - velocity
        
        zero at maximum height
        
        changes allong the trajectory
        
        can be calculated with
        
        v=u+at
        
        where
        
        v=0
        
        u=usinθ
        
        a=-g=-9.8
        
        t=?
      - acceleration
        
        Acceleration of free fall, g = 9.8 ms−2
        
        acceleration is a constant
      - displacement
        
        Maximum height is at the top of the motion when half the time has elapsed
        
        can be calculated with
        
        v^2=u^2 + 2as
        
        where
        
        v=0
        
        a=-g
        
        u=usinθ
        
        s=?
    - - the resultant velocity can be split in horizontal and vertical vector components using trigonometry
      - horizontal component
        
        adjacent side of the projectile triangle
        
        u cosθ
      - vertical component
        
        opposite side of the projectile triangle
        
        u sinθ
  - - - turns negative
    - - decreases
    - - decreased
    - - no longer a parabola
    - - decreases
    - - decreases
  - - - The frictional force from fluid resistance increases as the body accelerates
        
        Due to Newton’s Second Law, this means the resultant force and therefore acceleration decreases
        
        When the viscous drag force is equal to the weight on the body, the body will no longer accelerate and will fall at a constant velocity
        
        This velocity is called the terminal velocity
        
        This increase in velocity means the viscous drag force also increases
- - - - can be positive or negative
        
        speeding up
        
        acceleration (+)
        
        slowing down
        
        deceleration (-)
- - - - when a(acceleration) is missing
    - - When t(time) tis missing
    - - When v(final velocity) is missing
    - - When U8initial velocity) is missing
    - - when s(displacement is missing)
  - - - u=0
    - - a=g=-9.8ms^-2
    - - v=x
- - - - Slope =velocity
      - y-intercept =initial displacement
      - straight (diagonal) line represents a constant velocity
      - curved line represents an acceleration
      - positive slope represents motion in the positive direction
      - negative slope represents motion in the negative direction
      - zero slope (horizontal line) represents a state of rest
      - The area under the curve is meaningless
  - - - Slope =acceleration
      - The y-intercept =the initial velocity
      - A straight (diagonal) line represents uniform acceleration
      - A curved line represents non-uniform acceleration
      - A positive slope represents acceleration in the positive direction
      - A negative slope represents acceleration in the negative direction
      - A zero slope (horizontal line) represents motion with constant velocity
      - The area under the curve equals the change in displacement
  - - - Slope is meaningless
      - The y-intercept equals the initial acceleration
      - A zero slope (horizontal line) represents an object undergoing constant acceleration
      - The area under the curve equals the change in velocity
      - A straight (diagonal) line represents increasing acceleration
- - - - direction is not relevant
      - magnitude is relevant
  - - - magnitude is relevant
      - direction is relevant
    - - The overall displacement of the student would be a straight line between their home and school, regardless of any obstacles,
      - The overall distance they travel includes the total length of all the roads, including any twists and turns
- - - - magnitude is relevant
      - direction is not relevant
    - - avarage speed=distance/time
      - measured in meters per second (ms^-1)
  - - - magnitude is relevant
      - direction is relevant
    - - avarage velocity=displacement/total time taken(v=s/t)
      - if acceleration is constant
        
        avarage velocity= initial velocity + final velocity/2 (v=(u+v)/2)
        
        change in velocity
        
        final velocity-initial velocity (Δv=v-u)
    - - velocity is scalar
        
        velocity can have negative values
      - speed is scalar
        
        speed will always be positive
      - velocity is the speed in a given direction