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Séries de Fourier - Coggle Diagram

- - - - Temos então que:
        
        Portanto \(SW(t) = \sum_{n=1}^{\infty} \frac{2}{\pi}\frac{(1-(-1)^{n})}{n}sin(nt)\)
        
        \(a_0 = \frac{1}{\pi}\int_{-\pi}^{\pi} [2(H(t)-H(t-\pi))-1]\,dt = 0\)
        
        \(a_n = \frac{1}{\pi}\int_{-\pi}^{\pi} [2(H(t)-H(t-\pi))-1]cos(nt)\,dt = 0\)
        
        \(a_n = \frac{1}{\pi}\int_{-\pi}^{\pi} [2(H(t)-H(t-\pi))-1]sin(nt)\,dt = \frac{2}{\pi}\frac{(1-(-1)^{n})}{n}\)
      - \(a_0 = \frac{1}{2\pi}\int_{-\pi}^{\pi} SW(t)\,dt\)
      - \(a_n = \frac{1}{\pi}\int_{-\pi}^{\pi} SW(t)cos(nt)\,dt\)
      - \(b_n = \frac{1}{\pi}\int_{-\pi}^{\pi} SW(t)sin(nt)\,dt\)
      - Vemos que podemos substituir \(SW(x)\) por \(2(H(t)-H(t-\pi))-1\), onde \(H(x)\) é a função de Heaviside.