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Impulse - Momentum - Angular momentum, CONSERVATION THEOREM - Coggle…

- - - - ( m * dV ) / dt
        
        Σ Fe = dQ / dt
        
        Σ (Fex) = dQx / dt
        Σ (Fey) = dQy / dt
        
        ∫ ( Σ (Fex) dt ) = dQx
        ∫ ( Σ (Fey) dt ) = dQy
        
        ∫ ( Σ (Fex) dt ) = mV2x - mV1x
        ∫ ( Σ (Fey) dt ) = mV2y - mV1y
        
        Linear Momentum
        Q = Σ mi * Vi = mT * VG
        
        Linear impulse
        Fe dt = ∆ m V
        
        IMPULSE THEOREM
- - - - p x m * dV /dt
        
        Σ MeG = dKG / dt
        
        ∫ ( M * dt ) = K2 - K1
        
        Angular Momentum
        KG = Σ pi x mi * vi
        
        Conservation of linear momentum
        dQ / dt = Σ Fe = 0, Q = const
        Conservation of angular momentum
        dKG / dt = Σ MG = 0, KG = const
        
        KG = Σ ρi x mi * vi
        
        vi = ω * ρi
        
        KG = ρi^2 * mi * ω
        
        KG = IG * ω
        
        1 more item...
        
        IG = ∫ ρ^2 dm
        
        1 more item...
        
        Angular impulse
        Mo * dt = ∆ p x (m * V)
        
        consider:
        p = distance of generic point P from G
        mt = total mass
        VG = velocity of the center of mass
        
        KP = KG + p x mt * VG
        
        EQUILIBRIUM EQUATIONS
        dQG / dt + Fi = 0
        dKG / dt + MiG = 0
        
        KG = p x m *dV