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Python Basic Interview - Coggle Diagram

- - - - str(5) = '5'
    - - is
      - ==
    - - .istitle()
    - - 'string1' in 'string2'
    - - 'string1'.find('string2')
        
        -1 means not found
      - 'string1'.index('string2')
        
        ValueError:substring not found
        
        search for specific part of string
        
        'string1'.index('string2',10, 44)
    - - 'string1'.count('s')
    - - .capitalize()
    - - f'xxx {s1} and {s2} xxx'
    - - 'xxx{} and {}'.format(string1, string2)
    - - string1.isnumeric()
    - - string1.split(' ')
      - string1.split('--')
    - - string1[0].islower()
    - - ''.join(reversed('string1'))
    - - '-'.join['string1', 'string2', 'string3']
      - x = "#".join(myTuple)
      - s2="".join(L2)
      - remove all whitespace from a string
        
        ''.join(s.split())
    - - string1.upper(); string1.lower()
    - - string1.isupper()
    - - string1.splitlines()
    - - string[:6]
      - string[0:10:2]
    - - string1.isalpha()
    - - string1.replace(string2, string3)
      - s.replace(' ', '')
    - - lstrip()
      - rstrip()
      - strip()
    - - string1.startswith(string2)
      - string1.endswith(string2)
    - - string1.title()
    - - string1 + string2
    - - verify by id(string1)
  - - - len(), max(), min, sum, sorted()
      - tuple(list1) or tuple(string1)
  - - - len(list1), max(list1), min(list1), sum(list1), sorted(list1)
      - list1.append(value), copy(), count(value), list1.extend(list2), list1.insert(index, value)
      - pop() - return index of the removed item, remove(), clear()
      - list1.reverse(), list1.sort()
      - list(tuple1) or list(string1)
    - - list[:n], list[n:], list[n1:n2], list[n1:n2:step]
    - - list(set(list1))
  - - - s1.add(value)
      - pop(), remove()
      - discard()
      - s1.update(s2)
      - intersection(), difference()...
  - - - update, add, or remove key-value pairs at any time.
      - If you use Python 3.6 or earlier , you have to use an OrderedDict to guarantee the order of your dictionary.
        
        od = OrderedDict()
    - - more_languages = dict(scala=1, rust=2, golang=0, python=10)
      - d1 = {"a": 1, "b": 2, "c": "term"}
      - languages = ("python", "julia", "R") ; ratings = (1,2,3); dict(zip(languages, ratings))
      - d = dict()
    - - for key in ds_languages:
    - - for key, value in dictionary_1.items():
      - print(f"{key} and {value}")
    - - 1
    - - ds_languages.update(more_languages)
        
        d1.update(d2)
      - Remove items
        
        popped_item_or_none = ds_languages.pop(key, None) # Remove given key-value pair in place
        
        last_added_item = ds_languages.popitem() # Removes last added item inplace
    - - combined = { ds_languages, more_languages}
    - - dictionary_nested = {"datacamp":{"Deep Learning": "Python", "Machine Learning": "Pandas"},"linkedin":"jobs","nvidia":"hardware"}
        
        dictionary_nested['datacamp']['Deep Learning']
    - - added_10 = {key: value + 10 for (key, value) in scores.items()}
      - has_passed = {key: True if value > 50 else False for (key, value) in scores.items()}