Electromagnetics

Magnetic Fields

Electric Fields

Magnetic Field created by a toroid of N turns

C1 - surface within the centre hole of the toroid - no current passes through this circular surface

C2 - surface through the centre of the toroid itself - N amounts of current I pass downwards through the surface, none flows upwards

amperes law 0

amperes law uIN

C3 - surface around outside of toroid - N amounts of current I pass downwards through the surface, and same amount upwards so net current flow is zero

amperes law 0

toroid b

Inductance of a Toroid with N turns of wire

amperes law uIN

B is perpendicular to dl

toroid b2

lfux a

flux t

inductance toroid

Magnetic Field due to current carrying wire

m field die to wire

biot savart

S WIRE

sin

sd

fg

dhsjc

Capacitance of a Coaxial Capacitor

coax cap

Gauss' Law to go from charge to electric field strength

gauss

Due to symmetry, electric field strength will be same at all points on surface of Gaussian cyclinder and acts perpendicular to all surface elements so parallel to area vector

co cap

poten co cap

dl dr

v

capc

Energy in a charged capacitor

energy cap

Electric Energy Density

ee dens

vol

dens

Capacitance of Parallel Plate Capacitor

calculate E1 due to positive plate

gauss

charge enclosed by Gaussian cuboid: ρA = Q

e1

E between plates = E1 + E2 = 2E1

e

vv

cap parr

Magnetic Field due to a solenoid

solenoid

amperes law uIN

AB: dl parallel to B so B.dl = BS

mag solen

AD: B perpendicular to dl so B.dl = 0

BC: B perpendicular to dl so B.dl = 0

DC: outside solenoid so B=0 - ampere's law is zero

length S, n turns per metre

Potential Difference at point P due to continuous line charge

line

potenti

Electric Field produced by infinitely long line charge

Cylindrical Gaussian surface, length L, around line

EMF induced in closed circuit travelling with velocity v in uniform magnetic field B

Edge 1: From y = 0 to y = s, B = 0 as relevant part of frame is outside magnetic field

mot emf

Edges 2 and 3: dl parallel to v therefore v x dl = 0

Edge 4: dl perpendicular to B and v so v x dl = 1

force on parts of wire that are inside B acts upwards - force is on sides of the wire so doesn't contribute to EMF

mot emf 2

dl dy

mot emf 3

v x dl parallel to B so B.(v x dl) = 1

Capacitance of speherical capacitor

gauss

gauss sphere

v speh

c speh