Consider \(N_{11}\), the number of males who are promoted. Under \(H_0\), the distribution of \(N_{11}\) is that of the number of successes in 24 draws without replacement from a population of 35 successes and 13 failures; that is, the distribution of \(N_{11}\) is hypergeometric \(H(N, n, r)=H(48, 24, 35)\) Vi får alltså t.ex.