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Problem 3 & 4 - signal detection & colour (Problem 3 (Signal…

- - - - difference from 0 when you are able to identify a stimulus
    - - Method of constant stimuli
        
        sequence of tones is chosen
        
        randomly presented in many trials
        
        not practical
        
        threshold is arbitrary
      - Method of limits
        
        ascending sequence
        
        descending sequence
        
        average of result of the two
        
        absolute threshold not a fixed value
      - adaptive testing
        
        tone presented until heard, then again going up and down until threshold reached again
        
        adjusting stimuli contantly
  - - - liberal
      - neural
      - consercative
    - - to shift criterion of participant
    - - noise no stimulus
      - noise and stimulus
      - overlap = low sensitivity
      - sensitivity = d' = distance between peak and peak
  - - - interval of uncertainty
        
        = just noticible differnece
- - - - L = long
      - M = medium
      - S = short
    - - e.g. blue = high stiumlation of S
        then lower of M and least of L
    - - 3 only lets you see more colours
    - - only see shades of lightness
  - - - opposing afterimages
      - people who can't see red can also not see green
    - - black (-) white (+)
        red (-) green (+)
        blue (-) yellow (+)
  - - - Protanopia
        
        see S&M can't see L
      - Deuteropia
        
        can't see M but S&L
      - Tritanopia
        
        miss S but have M&L
    - - can't distinguish wavelength