引入无量纲参量:\( \frac{d^2}{d\xi^2}\psi + (\lambda - \xi^2)\psi =0 \)
渐进解:\( n \to \infty, \frac{d^2}{d\xi^2} \psi - \xi^2 \psi = 0 \)
解得: \( \psi \sim e^{-\xi^2 / 2} \) (束缚态约束)
假设:\( \psi = e^{-\xi^2/2}u(\xi) \)
得出Hermite方程:\( \frac{d^2}{d\xi^2}u-2\xi \frac{d}{d\xi} u+ (\lambda -1 )u = 0 \)
为了有多项式解:\( \lambda - 1 = 2n, n=0,1,2,.... \)
所以:\(E_n = (n +1/2 ) \hbar \omega, n=0,1,2,... \)